A box contain 3 dimes, 3 nickels and 1 penny .3 coins are being selected at random without replacement .(Where 1 Dime=10 cent, 1 Nickle=5 cent and 1 penny=1 cent)

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3 dimes, 3 nickels and 1 penny

Total = 3+3+1=7

To find the probability that 3 coins selected are dimes.

Required probability $=\dfrac{3}{7}$

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