Solution to Daniel went to the perya and played a game. The rule says that the outcome … - Sikademy
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Peace Awoke

Daniel went to the perya and played a game. The rule says that the outcome of the game is a random variable from 1 to 14 and that if the outcome is even, he wins ₱50. If the outcome is odd, he wins nothing. Assuming that playing is for free, what is Daniel’s expected gain, if there is any?

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There are 7 odd numbers and 7 even numbers


P(X=odd)=\dfrac{7}{14}=\dfrac{1}{2}=P(X=even)

Then


E(X)=0(\dfrac{1}{2})+50(\dfrac{1}{2})=25

 Daniel’s expected gain is ₱25.

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Question ID: mtid-4-stid-46-sqid-4275-qpid-1105