Given a standard normal distribution with mean =61 and standard deviation = 35, find P(X<113)

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$\mu=61\\\sigma=35$

$p(x\lt 113)=p({x-\mu\over \sigma}\lt {113-\mu\over\sigma})=p(Z\lt{113-61\over35})=p(Z\lt1.49)=0.93119$

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