In an achievement test, the mean score of normally distributed values is 70 and the standard deviation is 12. What is the percentage of students who got a score of 85 and above?

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$P (X \geq 85) = 1 - P (X < 85)$

$=1-P(Z<\dfrac{85-70}{12})=1-P(Z<1.25)$

$\approx0.10565$

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