In a certain town, 40% of the eligible voters prefer candidate A, 10% prefer candidate B, and the remaining 50% have no preference. You randomly sample 10 eligible voters. What is the probability that 4 will prefer candidate A, 1 will prefer candidate B, and the remaining 5 will have no preference?
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Solution:
Here we are given that P(A) = 0.4, P(B) = 0.1 and P(nil ) 0.5
Also n = 10 is the sample size
a) Probability that 4 prefers A, 1 prefer B and 5 will have no preference is computed as:
Therefore 0.0024 is the required probability here.