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There are 5 defective light bulbs in a bin containing 60 light bulbs.How many ways can you choose at least 4 defective light bulbs at random

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4 defective and 2 non-defective bulbs could be selected in C_5^4*C_{55}^2=7425\;ways.

5 defective and 1 non-defective bulbs could be selected in C_5^5*C_{55}^1=55\;ways.

So the number of ways at least 4 defective bulbs can be selected when 6 bulbs are drawn randomly:

N=7425+55=7480.

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Question ID: mtid-4-stid-46-sqid-2328-qpid-798