Solution to There are three Groups A,B and C with no. of persons 50, X, 90. The … - Sikademy
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Archangel Macsika

There are three Groups A,B and C with no. of persons 50, X, 90. The mean and Standard deviations for these groups are 113, Y, 115 and 6, 7, Z respectively. The Combind n , mean and Standard deviation for three groups are 200,116 and 7.746. (i) What is n ( The value of X ) for Group II . (ii) Mean (Value of Y ) of Group II? (iii) S.D. (Value of Z) of Group III ?

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(i)


50+X+90=200

X=60

(ii)


\dfrac{50(113)+60Y+90(115)}{200}=116

6Y=2320-565-1035

Y=120

(iii)


(7.746)^2=\dfrac{50(6)^2+60(7)^2+90(Z)^2}{200}

+\dfrac{50(113-116)^2+60(120-116)^2+90(115-116)^2}{200}

90(Z)^2=5760.1032

Z=8

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Question ID: mtid-4-stid-46-sqid-1891-qpid-361