Three balls are drawn in succession without replacement from an urn containing 3 red balls, 2 blue balls and 2 yellow balls. Let Z be the random variable representing the number of blue balls. Sample space (all outcomes) Possible values Properties 1 and 2 Probability Mass Function Histogram
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Solution:
3 red balls, 2 blue balls and 2 yellow balls.
Three balls are drawn in succession without replacement.
Z be the random variable representing the number of blue balls.
(a) S={RRR, RRB, RRY, BBR, BBY, YYR, YYB, BYR}
(b) Possible values of Z = {0,1,2}
(c) Properties 1 and 2 do not make sense. It is incomplete data.
(d) Probability Mass Function:
P(Z=0)=3/8 = 37.5%
P(Z=1)=3/8=37.5%
P(Z=2)=2/8 = 1/4=25%
(e)Histogram: