5. What is the probability that a market inspector will discover, greater than five violations of the public health code?

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Let the random variable $X$ represent the number of violations of the public health code.

The probability that a market inspector will discover greater than 5 violations of health code is

$P(X\gt5)=1-P(X\le5)=1-P(X=0)$

$-P(X=1)-P(X=2)-P(X=3)$

$-P(X=4)-P(X=5)$

$=1-0.41-0.22-0.17-0.13-0.05-0.02$

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