Solution to An electrical firm manufactures light bulbs that have a length of life that is normally … - Sikademy
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Peace Weguma

An electrical firm manufactures light bulbs that have a length of life that is normally distributed with mean equal to 809 hours and a standard deviation of 48 hours. Find the probability that a bulb burns between 728 and 848 hours

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Let X= a length of life: X\sim N(\mu, \sigma^2).

Given \mu=809\ h, \sigma=48\ h.


P(728<X<848)=P(X<848)-P(X\le 728)

=P(Z<\dfrac{848-809}{48})-P(Z\le \dfrac{728-809}{48})

= P(Z<0.8125)-P(X\le -1.6875)

\approx0.79175-0.04575= 0.7460

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