Solution to A bag contains 8 blue and 7 yellow balls. Two balls are drawn in succession … - Sikademy
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Loveth Chisimdirim

A bag contains 8 blue and 7 yellow balls. Two balls are drawn in succession without replacement. Find the probability that both the balls are of yellow color.

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The total number of balls is, 8+7=15 balls.

The probability that a blue ball is selected is p(blue)={8\over15}

The probability that a yellow ball is selected is p(yellow)={7\over15}

The probability that two balls drawn in succession without replacement are both yellow in is {7\over15}\times{6\over14}={42\over210}={1\over5}

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