Solution to a car salesperson as arrange a visit on three perspective customers in a week based … - Sikademy
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Mirian Woke

a car salesperson as arrange a visit on three perspective customers in a week based on the past experiences helpers and laws that there is 10% chance of closing a sale on each visit determine the probability distribution of the number of sales and persons will make

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This is a binomial distribution with n=3,p=0.1.

P(X=0)=C_3^00.1^00.9^3=0.729.

P(X=1)=C_3^10.1^10.9^2=0.243.

P(X=2)=C_3^20.1^20.9^1=0.027.

P(X=3)=C_3^30.1^30.9^0=0.001.

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