Given a standard normal distribution with mean =62 and standard deviation = 44, find P(X>92)

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$P (X > 92) = 1 - P (X \leq 92) =$

$=1-P(Z\leq\dfrac{92-\mu}{\sigma})=1-P(Z\leq\dfrac{92-62}{44})$

$\approx 1-P(Z\leq0.681818)\approx0.247677$

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Question ID: mtid-4-stid-47-sqid-5208-qpid-927