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Given a population of 5000 scores with a mean of 86 and a standard deviation of 10, how many scores are above 116?

$P(X>116)=1-P(X\le 116)$

$=1-P(Z\le \dfrac{116-86}{10})=1-P(Z\le3)$

$=0.00135$

$0.00135(5000)=7$

7 scores are above 116.

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Question ID: mtid-4-stid-47-sqid-4687-qpid-406