A meeting of consuls was attended by 4 Americans and 2 Germans. If three consuls were selected at random, construct the probability distribution of the random variable G representing the number of Germans

The Answer to the Question
is below this banner.

Can't find a solution anywhere?

NEED A FAST ANSWER TO ANY QUESTION OR ASSIGNMENT?

You will get a detailed answer to your question or assignment in the shortest time possible.

Here's the Solution to this Question

Americans: A = 4

Germans: G = 2

Total = 6

3 out of 6 can be selected in ⁶C₃ = 20 Ways

Germans can be 0 , 1 or 2

The number of Germans can not be 3 because they are only 2 in number.

three consuls were selected

G = 0 => ⁴C₃ x ²C₀ = 4 Ways

G = 1 => ⁴C₂ x ²C₁ = 12 Ways

G = 2 => ⁴C₁ x ²C₂ = 4 Ways

G P (G)

0 ${4\over20} =0.2$

1 ${12\over20} =0.6$

2 ${4\over20} =0.2$