Solution to A spinner for a child's game has the numbers 1 through 9 evenly spaced. If … - Sikademy
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A spinner for a child's game has the numbers 1 through 9 evenly spaced. If a child spins, find each probability: a. The number is divisible by 3. b. the number is greater than 7. c. The number is an even number.

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Sample space = {1,2,3,4,5,6,7,8,9}

Total number of outcomes = 9

a. Number divisible by 3 in the sample space = 3, 6, 9

Thus, no. of favourable outcomes = 3

Required probability = \frac{3}{9}=\frac{1}{3}

b. Number greater than 7 in the sample space = 8, 9

Thus, no. of favourable outcomes = 2

Required probability = \frac{2}{9}

c. Even number in the sample space = 2, 4, 6, 8.

Thus, no. of favourable outcomes = 4

Required probability = \frac{4}{9}

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Question ID: mtid-4-stid-47-sqid-5142-qpid-861