Solution to 4. The probabilities that a printer produces 0, 1, 2, and 3 misprints are 42%, … - Sikademy
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Loveth Chisimdirim

4. The probabilities that a printer produces 0, 1, 2, and 3 misprints are 42%, 28%, 18%, and 12%, respectively. Construct the probability Mass function and then compute the mean value of the random variable.

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We define the probability mass function as

x 0 1 2 3

P(x) 0.42 0.28 0.18 0.12


The mean is obtained as below

= ( 0 * 0.42) + ( 1 * 0.28) + ( 2 * 0.18) + ( 3 * 0.12)


= ( (0.28) + (0.36) + ( 0.36) ) = 1.00 which is the required mean.

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