Solution to the probabilities that a student gets 0, 1,2,3,4, or 5 mistakes are respectively. What is … - Sikademy
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Mirian Woke

the probabilities that a student gets 0, 1,2,3,4, or 5 mistakes are respectively. What is the average number of mistakes that a student makes in this class? What is expected value, variance and standard deviation of this discrete probability distribution?

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mean=E(X)=0.12(0)+0.25(1)+0.36(2)

+0.14(3)+0.08(4)+0.05(5)=1.96

E(X^2)=0.12(0)^2+0.25(1)^2+0.36(2)^2+0.14(3)^2

+0.08(4)^2+0.05(5)^2=5.48

Var(X)=\sigma^2=E(X^2)-(E(X))^2

=5.48-(1.96)^2=1.6384

\sigma=\sqrt{\sigma^2}=\sqrt{1.6384}=1.28

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