The weights of 1,000 children, in average, is 61kg with standard deviation of 10kg. Suppose the weights are normally distributed, how many children weigh less than 60kg?

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Let $X=$ weight: $X\sim N(\mu, \sigma^2 ).$

Given $\mu=61 \ kg, \sigma=10\ kg.$

$P(X<60)=P(Z<\dfrac{60-61}{10})$

$=P(Z<-0.1)\approx 0.460172$

460 children weigh less than 60kg.

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Question ID: mtid-4-stid-47-sqid-4972-qpid-691