Solution to Project Euler Problem 1: Multiples of 3 and 5 - If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. Find the sum of all the multiples of 3 or 5 below 1000.

• Java Code

package sikademy;
/**
 *
 * @author Archangel Macsika
 * Solution to Project Euler Problem 1: Multiples of 3 and 5
 * Copyright (c) Sikademy. All rights reserved
 */
public class SikademyEulerSolution {
	
	public String run() {
		int sum = 0;
		for (int i = 0; i < 1000; i++) {
			if (i % 3 == 0 || i % 5 == 0)
				sum += i;
		}
		return Integer.toString(sum);
	}

	public static void main(String[] args) {
                SikademyEulerSolution solution = new SikademyEulerSolution();
		System.out.println(solution.run());
	}	
}

• Python Code

# 
# Copyright (c) Sikademy. All rights reserved.
# @author Archangel Macsika
# 

def compute():
	ans = sum(x for x in range(1000) if (x % 3 == 0 or x % 5 == 0))
	return str(ans)


if __name__ == "__main__":
	print(compute())