Solution to Project Euler Problem 29: Distinct powers - Consider all integer combinations of ab for 2 ≤ a ≤ 5 and 2 ≤ b ≤ 5: If they are then placed in numerical order, with any repeats removed, we get the following sequence of 15 distinct terms: 4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125 How many distinct terms are in the sequence generated by ab for 2 ≤ a ≤ 100 and 2 ≤ b ≤ 100?
Updated: Oct. 2, 2023 — Training Time: 2 minutes
Overseen by: Archangel Macsika
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Topic: Project Euler Problem 29: Distinct powers.
Difficulty: Easy.
Objective: Consider all integer combinations of ab for 2 ≤ a ≤ 5 and 2 ≤ b ≤ 5:
22=4, 23=8, 24=16, 25=32
32=9, 33=27, 34=81, 35=243
42=16, 43=64, 44=256, 45=1024
52=25, 53=125, 54=625, 55=3125
If they are then placed in numerical order, with any repeats removed, we get the following sequence of 15 distinct terms:
4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125
How many distinct terms are in the sequence generated by ab for 2 ≤ a ≤ 100 and 2 ≤ b ≤ 100?
Input: None.
Expected Output: 9183.
Sikademy Solution in Java Programming Language
package sikademy;
/**
*
* @author Archangel Macsika
* Copyright (c) Sikademy. All rights reserved
*/
import java.math.BigInteger;
import java.util.HashSet;
import java.util.Set;
public class SikademyEulerSolution {
public String run() {
Set generated = new HashSet<>();
for (int a = 2; a <= 100; a++) {
for (int b = 2; b <= 100; b++)
generated.add(BigInteger.valueOf(a).pow(b));
}
return Integer.toString(generated.size());
}
public static void main(String[] args) {
SikademyEulerSolution solution = new SikademyEulerSolution();
System.out.println(solution.run());
}
}
Sikademy Solution in Python Programming Language
#
# @author Archangel Macsika
# Copyright (c) Sikademy. All rights reserved.
#
def compute():
seen = set(a**b for a in range(2, 101) for b in range(2, 101))
return str(len(seen))
if __name__ == "__main__":
print(compute())