Solution to Project Euler Problem 48: Self powers - The series, 1^1 + 2^2 + 3^3 + ... + 10^10 = 10405071317. Find the last ten digits of the series, 1^1 + 2^2 + 3^3 + ... + 1000^1000.


Updated: Oct. 19, 2021 — Training Time: 1 Minute
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Topic: Project Euler Problem 48: Self powers.

Difficulty: Easy.

Objective: The series, 11 + 22 + 33 + ... + 1010 = 10405071317.
Find the last ten digits of the series, 11 + 22 + 33 + ... + 10001000.

Input: None.

Expected Output: 9110846700.

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