Solution to Project Euler Problem 6: Sum square difference - The sum of the squares of the first ten natural numbers is, 1^2 + 2^2 + ... + 10^2 = 385 The square of the sum of the first ten natural numbers is, (1 + 2 + ...+ 10 = 55^2 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640. Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

• Java Code

package sikademy;
/**
 *
 * @author Archangel Macsika
 * Copyright (c) Sikademy. All rights reserved
 */

public class SikademyEulerSolution {
	
	private static final int N = 100;
	
	public String run() {
		int sum = 0;
		int sum2 = 0;
		for (int i = 1; i <= N; i++) {
			sum += i;
			sum2 += i * i;
		}
		return Integer.toString(sum * sum - sum2);
	}

	public static void main(String[] args) {
                SikademyEulerSolution solution = new SikademyEulerSolution();
		System.out.println(solution.run());
	}	
}

• Python Code

# 
# @author Archangel Macsika
# Copyright (c) Sikademy. All rights reserved.
# 

def compute():
	N = 100
	s = sum(i for i in range(1, N + 1))
	s2 = sum(i**2 for i in range(1, N + 1))
	return str(s**2 - s2)


if __name__ == "__main__":
	print(compute())