Create a program to discover which words in a list occurs only once and which occurs more than once, but you do not want any duplicates printed out repeatedly. This effect can be achieved by generating two sets: one containing every word in the argument list and the other containing only the duplicates. The words that occur only once are the set difference of these two sets.

• Java Code

package sikademy;
/**
 *
 * @author Archangel Macsika
 */
import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import java.util.logging.Logger;

// This class creates two list: one containing all words and one containing duplicates

public class DuplicateAndDistinctList {
	private static final Logger LOG = Logger.getLogger(DuplicateAndDistinctList.class.getName());

	public static void main(String[] args) {
		LOG.info("Into Main Class");
		String[] setOfWord = { "good", "bad", "good", "people", "time", "time" };
		List listOfAllWords = new ArrayList();
		List singleWords = new ArrayList();
		for (String str : setOfWord) {
			listOfAllWords.add(str);
		}
		for (String word : listOfAllWords) {
			if (Collections.frequency(listOfAllWords, word) == 1) {
				singleWords.add(word);
			}
		}
		LOG.info("The list of all words are : " + listOfAllWords);
		LOG.info("Words with single occurrence are : " + singleWords);
	}
}