Write a program that takes the words in a list and prints out any duplicate words, the number of distinct words, and a list of the words with duplicates eliminated. Hint: Try with HashSet and List implementation.

• Java Code

package sikademy;
/**
 *
 * @author Archangel Macsika
 */
import java.util.ArrayList;
import java.util.Collection;
import java.util.Collections;
import java.util.HashSet;
import java.util.Iterator;
import java.util.List;
import java.util.Set;
import java.util.logging.Logger;

// This class prints the duplicate, distinct and list of words with duplicate eliminated.

public class HashSetAndListImplementation {
	private static final Logger LOG = Logger.getLogger(HashSetAndListImplementation.class.getName());

	public static void main(String[] args) {
		LOG.info("Into main function");
		List<String> listOfWords = new ArrayList<String>();
		listOfWords.add("one");
		listOfWords.add("two");
		listOfWords.add("one");
		listOfWords.add("two");
		listOfWords.add("three");
		Iterator iterator;
		List<String> distinctList = new ArrayList<String>(new HashSet<String>(listOfWords));
		Set<String> duplicateWords = new HashSet<String>();
		for (String str : listOfWords) {
			if ((Collections.frequency(listOfWords, str)>1)){
				duplicateWords.add(str);
			}
		}
		LOG.info("showing duplicate words:");
		iterator = duplicateWords.iterator();
		while (iterator.hasNext()) {
			LOG.info("" + iterator.next());
		}
		LOG.info("Showing distinct words : ");
		iterator = distinctList.iterator();
		while (iterator.hasNext()) {
			LOG.info("" + iterator.next());
		}
	}

}